Consider the alternating group A4 = {σ ε S4 :σ is ...
Given A
4 = is an even permutation}
A
4 has a subgroup of order 6 is false.
Because in this example converse of Lagrange’s theorem fails.
Hence, option (c) is correct.
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Consider the alternating group A4 = {σ ε S4 :σ is ...
(), (1 2)(3 4), (1 3)(2 4), (1 4)(2 3) }.
The first element is the identity element, denoted as (). This element does not change any elements in the group when it is applied, so it is called the identity element.
The second element is a 2-cycle, denoted as (1 2)(3 4). This element swaps the elements 1 and 2, and also swaps the elements 3 and 4. It does not change the elements 5 and 6, so it is called a 2-cycle.
The third element is also a 2-cycle, denoted as (1 3)(2 4). This element swaps the elements 1 and 3, and also swaps the elements 2 and 4. It does not change the elements 5 and 6.
The fourth element is also a 2-cycle, denoted as (1 4)(2 3). This element swaps the elements 1 and 4, and also swaps the elements 2 and 3. It does not change the elements 5 and 6.
These four elements generate the alternating group A4, which consists of all possible permutations of 4 elements that can be obtained by composing these elements.
Consider the alternating group A4 = {σ ε S4 :σ is ...
Given A
4 = is an even permutation}
A
4 has a subgroup of order 6 is false.
Because in this example converse of Lagrange’s theorem fails.
Hence, option (c) is correct.